The 4 digit lock has 10,000 combinations.
One way to determine how many combinations that are possible with 4 numbers is to list them all, and then count the number of items in the list. These are all of the possible combinations of 4 numbers, and there are 15 combinations in this list, so the number of combinations possible with 4 numbers is 15.
How many different combinations can you make with the numbers 1234? So there are {1,2,3,4} these 4 numbers. So there are 64 total ways.
The total number of permutations is 6 x 4 = 24. There are 24 ways to arrange the 4 items on a bookshelf. You probably don't want to draw tree diagrams for every permutation problem.
(Although, as Data Genetics acknowledges, you probably shouldn't go out and choose “8068” now that this is public information.) Rounding out the bottom five are “8093,” “9629,” “6835,” and “7637,” which all nearly as rare.
The number of possible combinations with 4 numbers without repetition is 15. The formula we use to calculate the number of n element combinations when repetition is not allowed is 2n - 1.
Therefore, there are 9000 four digit numbers in all. Hence, the answer of this question is (c) 9000. Let us now find out the total number of three – digit numbers.
There are 720 permutations of the digits 1,2,3,4,5,6 supoose these permutations are arranged from smallest to largest numerical values beginning from 123456 and ending with 654321.
The 4x4x4 Rubik's cube (called the Master Cube, or Rubik's Revenge – not sure who he was avenging, I must say) has 7 401 196 841 564 901 869 874 093 974 498 574 336 000 000 000 combinations (that is, 7.4 quattuordecillion, if you really wanted to know).
How many combinations are there in a 4 letters + 4 digits code (example: AAAA0000)? If we assume your letters range from A to Z and your digits from 0 to 9, you have 26 possibilities per letter and 10 per digit. This gives you 26^4*10^4 which is roughly 4 billion and a half.
Formula for finding how many combinations you have
C(n, r) = (n!) / [(r!) x (n - r)!]
Answer and Explanation:
Therefore, the number of 5 digit combinations, if digits are repeated, can be calculated as 10 × 10 × 10 × 10 × 10 = 100 , 000 combinations.
To get the total number of combinations, we need to multiply the possibilities on both slots. Therefore, the number of two-digit numbers can be formed using 1, 2, 3, 4, 5 without repetition is 5 × 4 = 20 .
Thus you have made 5 × 4 × 3 × 2 1 = 120 choices and there are 120 possible 5 digit numbers made from 1, 2, 3, 4 and 5 if you don't allow any digit to be repeated.
nAnswer: 840" Was this answer helpful?
9999 is the largest 4 digit number.
The smallest 4-digit number is 1,000 and the largest 4-digit number is 9,999, and there are a total of 9000 numbers from 1000 to 9999.
Greatest 4−digit number of distinct four different digit =9876. Was this answer helpful?
Hence, 1,023 is the smallest and 9,876 is the greatest four-digit numbers without repetition of any digit. Q. Write the smallest and the greatest 5-digit numbers using the digits 0,2,4,6,8 (Repetition of digits is not allowed).
Hence total number of permutations = 9×504=4536.
6 x 5 x 4 x 3 = 360 possible combinations. Given a 4 digit integer. each digit can be 1 through 6.
Takes about 10 minutes to run through all possible combinations of numbers for most briefcases with the type of lock you described. Using letters from English alphabet instead of digits you have 26 x 26 x26 = 17,576 combinations.
The factory-set combination is 0-0-0. Push in the button at the bottom of the lock. While holding in the button, turn the dials to your new combination. Once the dials are set to your new combination, release the button.